Directions: You may work to solve these problems in groups, but all written work must be your own. Show all work; no credit for solutions without work..

  1. [5.3.4] Given the factorization A = 𝑃𝐷P1 below, find a formula for Ak where k is a nonnegative integer.

    [ 6 8 4 6 ] = [ 1 2 1 1 ] [ 2 0 0 2 ] [ 1 2 1 1 ]
  2. [5.3.{7-20}] Diagonalize the following matrices if possible. That is, for each diagonalizable matrix A below, construct an invertible matrix P and a diagonal matrix D such that A = 𝑃𝐷P1. (There is no need to compute P1 explicitly.) For each matrix A below that is not diagonalizable, explain why not.

    1. [ 1 0 6 1 ]
    2. [ 3 1 1 5 ]
    3. [ 1 4 2 3 4 0 3 1 3 ]
    4. [ 4 0 2 2 3 4 0 0 3 ]
    5. [ 2 0 0 0 0 2 0 0 0 0 2 0 1 0 0 2 ]
  3. [5.3.{21-28}] True/False. In the following, A, P, and D are (n ×n) matrices. Justify your answers.

    1. A is diagonalizable if A = 𝑃𝐷P1 for some matrix D and some invertible matrix P.
    2. If n has a basis of eigenvectors of A, then A is diagonalizable.
    3. A is diagonalizable if and only if A has n eigenvalues, counting multiplicities.
    4. If A is diagonalizable, then A is invertible.
    5. A is diagonalizable if A has n eigenvectors.
    6. If A is diagonalizable, then A has n distinct eigenvalues.
    7. If 𝐴𝑃 = 𝑃𝐷, with D diagonal, then the nonzero columns of P must be eigenvectors of A.
    8. If A is invertible, then A is diagonalizable.
  4. [5.3.31] A is a 4 × 4 matrix with three eigenvalues. One eigenspace is one-dimensional, and one of the other eigenspaces is two-dimensional. Is it possible that A is not diagonalizable? Justify your answer.
  5. Let 𝐯1 = [ 3 1 ] and 𝐯2 = [ 2 7 ], and let λ1 and λ2 be scalars. Construct a (2 × 2)-matrix A having eigenvectors 𝐯1 and 𝐯2 with respective eigenvalues λ1 and λ2. (Here, the entries of A will depend on λ1 and λ2.)